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NCERT Solutions 10th Maths Chapter 6 Triangles Exercise 6.4
NCERT Solutions For Class 10 Maths Chapter 6 Exercise 6.4 we will restart our exploration of the world of Triangles. Thus, we are providing you Chapter 6 Triangles NCERT Class 10 Maths Solutions that will help in achieving more marks. You don't have to wander and waste your precious time in finding best CBSE NCERT Solutions.
Exercise 6.4 1. 1. Let ΔABC ~ ΔDEF and their areas be, respectively, 64 cm2 and 121 cm2. If EF = 15.4 cm, find BC. Answer It is given that, Area of △ABC = 64 cm2 Area of △DEF = 121 cm2 EF = 15.4 cm and, △ABC ~ △DEF ∴ Area of △ABC/Area of △DEF = AB2/DE2 = AC2/DF2 = BC2/EF2 ...(i) [If two triangles are similar, ratio of their areas are equal to the square of the ratio of their corresponding sides] ∴ 64/121 = BC2/EF2 ⇒ (8/11)2 = (BC/15.4)2 ⇒ 8/11 = BC/15.4 ⇒ BC = 8×15.4/11 ⇒ BC = 8 × 1.4 ⇒ BC = 11.2 cm 2. Diagonals of a trapezium ABCD with AB || DC intersect each other at the point O. If AB = 2CD, find the ratio of the areas of triangles AOB and COD. AnswerPost your comments
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SEND ME ALL BITS FOR CLASS 1 TO 10
I want maths Book of class7
Send me all bits Bank pdf 1st to 10th class
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NCERT Solutions for Class 12
NCERT Solutions for Class 1 to 12, Free CBSE NCERT Solutions
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