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NCERT Solutions 10th Maths Chapter 4 Quadratic Equations Exercise 4.4
NCERT Solutions For Class 10 Maths Chapter 4 Exercise 4.4 we will restart our exploration of the world of Quadratic Equations. Thus, we are providing you Chapter 4 Quadratic Equations NCERT Class 10 Maths Solutions that will help in achieving more marks. You don't have to wander and waste your precious time in finding best CBSE NCERT Solutions.
Exercise 4.4 1. Find the nature of the roots of the following quadratic equations. If the real roots exist, find them; (i) 2x2 - 3x + 5 = 0 (ii) 3x2 - 4v3x + 4 = 0 (iii) 2x2 - 6x + 3 = 0 Answer (i) Consider the equation x2 - 3x + 5 = 0 Comparing it with ax2 + bx + c = 0, we get a = 2, b = -3 and c = 5 Discriminant = b2 - 4ac = ( - 3)2 - 4 (2) (5) = 9 - 40 = - 31 As b2 - 4ac < 0, Therefore, no real root is possible for the given equation. (ii) 3x2 - 4v3x + 4 = 0 Comparing it with ax2 + bx + c = 0, we get a = 3, b = -4v3 and c = 4 Discriminant = b2 - 4ac = (-4v3)2 - 4(3)(4) = 48 - 48 = 0 As b2 - 4ac = 0, Therefore, real roots exist for the given equation and they are equal to each other. And the roots will be -b/2a and -b/2a.-b/2a = -(-4v3)/2◊3 = 4v3/6 = 2v3/3 = 2/v3 Therefore, the roots are 2/v3 and 2/v3. (iii) 2x2 - 6x + 3 = 0 Comparing this equation with ax2 + bx + c = 0, we get a = 2, b = -6, c = 3 Discriminant = b2 - 4ac = (-6)2 - 4 (2) (3) = 36 - 24 = 12 As b2 - 4ac > 0, Therefore, distinct real roots exist for this equation:Post your comments
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