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MCQ Questions for Class 10 Maths Coordinate Geometry with Answers
MCQ Questions for Class 10 Maths Coordinate Geometry with Answers
Free PDF Download of CBSE Class 10 Maths Chapter 7 Coordinate Geometry Multiple Choice Questions with Answers. MCQ Questions for Class 10 Maths with Answers was Prepared Based on Latest Exam Pattern. Students can solve NCERT Class 10 Maths Coordinate Geometry MCQs with Answers to know their preparation level.
Class 10 Maths MCQs Chapter 7 Coordinate Geometry
1. The distance of the point P(2, 3) from the x-axis is
(a) 2
(b) 3
(c) 1
(d) 5
Answer/ Explanation
Answer: b
Explaination: Reason: The distance from x-axis is equal to its ordinate i.e., 3
2. The distance between the point P(1, 4) and Q(4, 0) is
(a) 4
(b) 5
(c) 6
(d) 3√3
Answer/ Explanation
Answer: b
Explaination: Reason: The required distance =
3. The points (-5, 1), (1, p) and (4, -2) are collinear if
the value of p is
(a) 3
(b) 2
(c) 1
(d) -1
Answer/ Explanation
Answer: d
Explaination: Reason: The points are collinear if area of Δ = 0
=
[-5(p + 2) +l(-2 -1) + 4(1 - p)] - 0
⇒ -5 p -10-3 + 4-4p = 0
⇒ -9p = +9
∴ p = -1
4. The area of the triangle ABC with the vertices A(-5, 7), B(-4, -5) and C(4, 5) is
(a) 63
(b) 35
(c) 53
(d) 36
Answer/ Explanation
Answer: c
Explaination: Reason: Area of ΔABC =
[x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2)]
=
[-5(-5 - 5) -4(5 - 7) + 4(7 - (-5))] =
[-5(-10) -4(-2) + 4(12)]
=
[50 + 8 + 48] =
× 106 = 53 sq. units
5. The distance of the point (α, β) from the origin is
(a) α + β
(b) α² + β²
(c) |α| + |β|
(d)
Answer/ Explanation
Answer: d
Explaination: Reason: Distance of (α, β) from origin (0, 0) =
6. The area of the triangle whose vertices are A(1, 2), B(-2, 3) and C(-3, -4) is
(a) 11
(b) 22
(c) 33
(d) 21
Answer/ Explanation
Answer: a
Explaination: Reason: Required area=
[1(3 + 4) -2(-4 - 2) -3(2 - 3)]
=
[7 + 12 + 3]
=
× 22 = 11
11. If the distance between the points (x, -1) and (3, 2) is 5, then the value of x is
(a) -7 or -1
(b) -7 or 1
(c) 7 or 1
(d) 7 or -1
Answer/ Explanation
Answer: d
Explaination: Reason: We have
⇒ (x - 3)² + 9 = 25
⇒ x² - 6x + 9 + 9 = 25
⇒ x² -6x - 7 = 0
⇒ (x - 7)(x + 1) = 0
⇒ x = 7 or x = -1
15. The area of the triangle formed by the points A(-1.5, 3), B(6, -2) and C(-3, 4) is
(a) 0
(b) 1
(c) 2
(d) 3/2
Answer/ Explanation
Answer: a
Explaination: Reason: Area of ΔABC =
[-1.5(-2 - 4) + 6(4 - 3) + (-3) (3 + 2)] =
[9 + 6 - 15] = 0. It is a straight line.
16. If the points P(1, 2), B(0, 0) and C(a, b) are collinear, then
(a) 2a = b
(b) a = -b
(c) a = 2b
(d) a = b
Answer/ Explanation
Answer: a
Explaination: Reason: Area of ΔPBC = 0
⇒
[1(0 - b) + 0(6 - 1) + a(2 - 0)] = 0
⇒
[-6 + 2a] = 0
⇒ -b + 2a = 0
∴ 2a = b
22. If the segment joining the points (a, b) and (c, d) subtends a right angle at the origin, then
(a) ac - bd = 0
(b) ac + bd = 0
(c) ab + cd = 0
(d) ab - cd= 0
Answer/Explanation
Answer: b
Explaination:
Let A {a, b), B(c, d), 0(0, 0)
∴ ∠AOB = 90°
⇒ AB² = AO² + BO²
(c - a)² + (d- b)² = a² + b² + c² + d²
⇒ ac + bd = 0